(a) q = +5.0 μC, v = 15.0 × 103
m/s, B = 0.25 T, θ = 65°![]() |
(b) q = -3.0 μC,
v = 6.0 × 103 m/s, B = 0.25 T, θ
= 122°![]() |
(c) q = +5.0 μC,
v = 15.0 × 103 m/s, B = 0.25 T ![]() |
(d) q = -5.0 μC,
v = 15.0 × 103 m/s, B = 0.25 T![]() |
(e) q = +5.0 μC,
v = 15.0 × 103 m/s, B = 0.25 T![]() |
(f) q = -5.0 μC,
v = 15.0 x× 103 m/s, B = 0.25 T![]() |


In diagram A below, two wires are carrying conventional currents,
I1 = 30.0 A and I2 = 22.0 A, in opposite
directions. Diagram B gives a head on perspective. Determine
the direction and magnitude of the net magnetic field at points
A, B, and C where r1 = 0.250 m, r2 = 0.350
m, r3 = 0.700 m, and r4 = 0.500 m.


Questions? mike.coombes@kwantlen.ca