1. In the diagram below, a block A of mass 3.00 kg is moving to the right when it collides with block B which has mass 4.50 kg and is not moving. The tabletop is frictionless and 1.20 m above the floor.
   (a) If the collision is perfectly elastic, block B lands 1.78 m from the edge of the table. Determine the initial and final velocities of each block.
   (b) If the collision is totally inelastic, and block A has the initial velocity determined in part (a), find where the blocks land.
   
   

2. In the diagram below, a ball of mass m = 0.020 kg is hanging by a thread from the ceiling. The thread makes an angle θ = 18.0° with the vertical. The ball has a positive charge q = 3.00 C. There is a negative charge Q = -2.00 C a distance r = 0.25 m away. There is also an unknown uniform electric field in the room, E, which points straight down. Determine the tension in the string. Determine the magnitude of the electric field.
   

3. In the diagram below are two charge q₁ = +5.00 C and q₂ = -4.00 C. The distances are r₁ = 20.0 cm and r₂ = 30.0 cm. The angle is θ = 58.0°. Determine the magnitude and direction of the electric field at point A. Determine the force acting on a charge Q placed at point A if Q is (i) 3.00 C, (ii) -7.00 C, or (iii) 2.00 C.
   

4. Five resistors are connected to a battery as shown in the diagram below. The five resistors are R₁= 3.00 Ω, R₂ = 4.00 Ω, R₃ = 12.00 Ω, R₄ = 2.00 Ω, and R₅ = 6.00 Ω. The battery supplies ε = 3.00 Volts. Find the equivalent resistance of the circuit. Find the current through each resistor. Find the voltage drop over each resistor. Find the power dissipated by each resistor.
   
   

5. A block has a speed of 2.85 m/s on top of a 1.50-m high hill. The hill surface is frictionless but the horizontal track has a coefficient of kinetic friction of μ = 0.27. Determine how far the block slides along the horizontal track before coming to a complete stop.
   
   

6. In the diagram below, a toy car has an unknown speed v at point A. It is known that the car just makes it (i.e. almost loses contact) around the inside of a loop-the-loop of radius R = 0.40 m. It then rolls up an incline to a height h where it comes to a complete rest. Determine the initial speed v and the height h. All work must be shown.
   
   

Formulas

Kinematics

		vaverage = ½(vf+v0)
Δx = vaveraget	Δx = v0t + ½at2	v = v0 + at
		g = 9.81 m/s2

Newton's Laws

ΣFx = max	ΣFy = may	fmax static = μsN	fkinetic = μkN
G = 6.672 × 10-11 N-m2/kg2

Work and Energy

W = FΔxcos θ = FxΔx

Wnc = ΔK + ΔP

K = ½mv2

P = mgh

Collisions

m1v1f + m2v2f = m1v1i + m2v2i	I = mvf - mvi = FaverageΔt
p = mv

Coulomb's Law and Electric Fields

F = qE	k = 8.99 × 109 N-m2/C2

Electric Circuits

V = IR	Rseries = R1 + R2 + ...
P = IR2 = IV = V/R2		Vvoltmeter = IG(Rcoil +Rmultiplier)

Quadratic Formula

if ax²+bx+c = 0, then

Questions? mike.coombes@kwantlen.ca