Questions: 1 2 3

Physics 1100: Math Review Solutions

1. Convert the following:
   

   (a) 72 km/h to metres per second (m/s).
   

   
   

   (b) 17.00 years to seconds.
   

   

   (c) 3.5 km² to square metres.
   

   
   (d) 33.0 cm³ to cubic metres
   

   

   (e) 2.55 g/cm³ to kg/m³
   

   
   

   (f) 35 m³/h to cm³/s
   

   
   

   

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2. In the triangles below, determine the length of the missing side using Pythagoras' theorem. Determine the angles in each triangle.
   

   
   

   C = [10²+15²]^½ = 18.0, α = tan^-1(15/10) = 56.3°, β = 90° - α = 33.7°
   

   
   

   A = [21²-8²]^½ = 19.4, α = cos^-1(8/21) = 67.8°, β = sin^-1(8/21) = 22.4°
   

   
   

   C = [3²+4²]^½ = 5, α = tan^-1(4/3) = 53.1°, β = 90 - α = 36.9°
   

   

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3. Compute the following:
   

   (a) 0.989 × 10⁴ × 2.456 × 10² = 2.43 × 10⁶ (3 Sig. Figs.)
   

   (b) 4.37 × 10² ÷ 3.21 × 10³ = 0.136 (3 Sig. Figs.)
   

   (c) 2.246 × 10⁵ + 7.81 × 10⁴ = 3.027 × 10⁵ (4 Sig. Figs.)
   

   

Questions? mike.coombes@kwantlen.ca