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(a) E = 5x2i. Calculate ΔV
between x = 0 m and x = 4 m.
(b) E = (2/y)j. Calculate ΔV
between y = 2 m and y = 5 m.
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Find the electrostatic potential difference between points A and B which
are distances rA = 2.0 m and rB = 1.0 m from an infinitely
long thin wire with λ = 1.0 μC/m.
The result E = λ/2pe0r
is useful. If an electron (q = -e = -1.602 × 10-19 C and
mass me = 9.11 × 10-31 kg) is released from
rest at point A, what is it's speed at point B?
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Find the electrostatic potential between points A and B which are distances
rA = 2.0 m and rB = 1.0 m from an infinitely large
thin plate with Σ = 1.0 μC/m2.
The result E = Σ/2ε0
is useful. If an electron (q = -e = -1.602 × 10-19 C and
mass me = 9.11 × 10-31 kg) is released from
rest at point A, what is it's speed at point B?.
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In Gauss’ Law question #7, we found the electric field due to a uniformly
charge long thick plate to be

where d was the thickness of the plate, ρ 0
was the volume charge density, and a is the distance from the centre
of the plate. Determine V(x) relative to V(0) where x is the distance from
the centre of the plate. Assume V(0) = 0. Plot V as a function of x.
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In Gauss’ Law question #8, we found the electric field due to a long thin
wire of uniform charge density λ to be E(a)
= (λ/2pe0a)r
where a is the radial distance from the wire and r
is the unit radial vector. Determine V(r) relative to V(r=1) where r is
the distance from the centre of the cylinder. Assume V(1) = 0. Plot V as
a function of r.
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In Gauss’ Law question #9, we found the electric field due to a long thin
cylindrical shell of radius R and negative surface charge density Σ
to be

where the field is radial (i.e. in the r direction). Determine
V(r) relative to V(r = 0) where r is the distance from the centre
of the cylinder. Assume V(0) = 0. Plot V as a function of r.
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In Gauss’ Law question #10, we found the electric field due to a solid
sphere of radius R and total charge Q to be radial and have the form

where the field is radial (i.e. in the r direction). Determine
V(r) relative to V(¥) where r is
the distance from the centre of the sphere. Assume V(r=¥)
= 0. Plot V as a function of r.
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In Gauss’ Law question #11, we found the electric field of a thick spherical
shell of total charge Q and inner and outer radii of R and 2R to be

where the field is radial (i.e. in the r direction). Determine
V(r) relative to V(¥)where
r is the
distance from the centre of the sphere. Assume V(¥)
= 0. Plot V as a function of r.
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In Gauss’ Law question #12, we found the electric field due to a thin spherical
shell of radius R and surface charge -s to be

where the field is radial (i.e. in the r direction). Determine
V(r) relative to V(r=¥) where r is
the distance from the centre of the sphere. Assume V(r=¥)
= 0. Plot V as a function of r.
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The electric field due to a large plate is E = Σ/2ε0
as we have seen. A capacitor consists of two identical plates with equal
but opposite charge distributions.
(a) Show that the net electric field is zero outside the plates and
Enet = Σ/ε0
between the plates.
(b) Show that the potential difference between the plates is directly
proportional to the separation d of the plates.
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Two point charges of q1 = 3.0 μC
and q2 = 4.0 μC are situated at the
opposite corners of a rectangle as shown below. The short side has length
L = 0.25 m. Find the total potential at points A and B. If a free particle
of charge qf = 1.0 μC and mass M
= 15 g has speed vA = 2.50 m/s at point A and it follows the
indicated path, what will be its speed at point B?

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Five charges are arranged as shown below. What is the electrostatic potential
energy of each configuration? The separation between charges is L.
(a)
(b)
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A rod is bent into a semi-circular arc of radius R. The rod has a uniform
linear charge distribution λ. Find the potential
at the centre of the arc, point P. The identity S= Rθ
and dS = Rdθ may be of use.

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A total charge Q is distributed uniformly along a straight rod of length
L. Find the potential at a point P at a distance h from the midpoint of
the rod. (Hint: ò[x2+k2]-½dx
= ln[x+[x2+k2]½] + C). Use the
gradient with respect to h to find the electric field at that point.

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Three thin rods of glass of length L carry charges uniformly distributed
along their lengths. The charges on the three rods are +Q, +Q, and -Q,
respectively. The rods are arranged along the sides of an equilateral triangle.
What is the electrostatic potential at the midpoint of this triangle? (Hint:
Use the result of the question 20-7.)

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The electric potential over a certain region is given by V = 3x2y-4xz-5y2
volts. Determine the components of the electric field and evaluate at the
point (+1,0,+2).
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Over a certain region of space, the electric potential is V = 5x-3x2y+2yz2.
Determine the components of the electric field and evaluate electric field
at the point (1,0,-2).