EXAMPLE: The diagram below shows a 'P'-shaped sign attached to a wall by a hinge and a wire. The sign is constructed of uniform material and has a mass m = 100.0 kg. The centre of the 'P' is a square 1m × 1m hole. Find the centre of mass of the sign.
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The 'P' has an area of 10 m2. Since it
is uniform, each 1m2 must have a mass of 10 kg.
| Piece | mi | xi | yi | mixi | miyi |
| 1 | 50 | 0.5 | 2.5 | 25.0 | 125.0 |
| 2 | 20 | 2.0 | 4.5 | 40.0 | 90.0 |
| 3 | 10 | 2.5 | 3.5 | 25.0 | 35.0 |
| 4 | 20 | 2.0 | 2.5 | 40.0 | 50.0 |
| Totals: | 100 | 130.0 | 300.0 |
Xcm = (Σmixi)/Mtotal = 130/100 = 1.30 m
Ycm =
(Σmixi)/Mtotal
= 300/100 = 3.00 m
Note that the hole having an area of 1 m2
has a mass of -10 kg. We 'fill' in the hole and subtract it later.

| Piece | mi | xi | yi | mixi | miyi |
| 1 | 90 | 1.5 | 3.5 | 135.0 | 315.0 |
| 2 | 20 | 0.5 | 1.0 | 10.0 | 20.0 |
| 3 | -10 | 1.5 | 3.5 | -15.0 | -35.0 |
| Totals: | 100 | 130.0 | 300.0 |
Xcm = (Σmixi)/Mtotal = 130/100 = 1.30 m
Ycm =
(Σmixi)/Mtotal
= 300/100 = 3.00 m
Exactly as before.
Questions? mike.coombes@kwantlen.ca